Pointers to Multidimensional Arrays

Hi there,

I have a problem that I can't seem to resolve. I know that if we have, say, an integer array A[5], then we can initialise a pointer to an integer as follows:

int* B = A;

But I can't seem to figure out what kind of pointer can be initialised to the name of a multidimensional array. For instance, if I have A[5][5], and I want to initialise B to A:

X B = A;

what should X be?

Thanks a lot for your help.

Sincerely,

shred2er.

well ,
it should be
int *B=A

this will store the base address that is the starting address of array A ,the 2-d array are stored as linear array internally :)

Hi vanika,

Thanks for the response. I had already tried that before posting, but unfortunately it does not work.

In my program I have defined an array A[3][3]. Then I tried to initialise a pointer to an integer B as follows: int* B = A. The compile-time error is:

Quote:

---

MatrixOperations.C: In function `int main (int, char **)':
MatrixOperations.C:50: cannot convert `int (*)[3]' to `int *' in
initialization

---

I have also tried int** B = A. There is noe that does not give any compile-time error: int* B = A[5]. But dereferencing B does not produce the desired results.

But I thank you for your trouble. Perhaps you have some other ideas as well?

Sincerely,

shred2er.

int (*B)[3] = A


if I remember correctly, its been a long time

Try specifying to the pointer that it has to point to the first element in the array.


For example
int A[2][2];
int*C;
C=&A[0][0];


tell me if it gives you any errors

Quote:

---

Originally posted here by Q-bel
Try specifying to the pointer that it has to point to the first element in the array.


For example
int A[2][2];
int*C;
C=&A[0][0];


tell me if it gives you any errors

---

Woohoo! Thanks, Q-bel! It works!

No problem man just as they've been helping me learn here I gotta try and help out at least in what I can jeje.

:eek: :eek: