coded time calcultator, but the hard way i think..

hi guys,

i'm still learning C, and one of the assignments of a tutorial was to code a time calculator, well i did, and it works fine, but i think it can be done a lot easier, just don't know how, perhaps there is some library for it...

here's the source:

Code:

---

#include <stdio.h>

int main()
{
        int time,time_hours,time_minutes;
        int duration,duration_hours,duration_minutes;
        int end_hours,end_minutes;
        time_minutes=61;/*make sure the while loop will start to run*/
        time_hours=25;/*make sure the while loop will start to run*/
        duration_minutes=61;/*make sure the while loop will start to run*/
        duration_hours=25;/*make sure the while loop will start to run*/
        printf("\nThis program allows you to calculate the end time");
        printf("\nwhen you enter the start time and duration.");
        printf("\nUsage: 1234 is 12 hours,34 minutes, so always enter");
        printf("\nyour times like this.\n\n");
        while((time<0) || (time_minutes > 59) || (time_hours > 23))/*bounds check*/
                {
                        printf("\nEnter the start time: ");
                        scanf("%d",&time);
                        time_minutes=time%100;/*calculate time hours and minutes*/
                        time_hours=(time-time_minutes)/100;                       
                }
        while((duration<0) || (duration_minutes > 59) || (duration_hours > 23))/*bounds check*/
                {
                        printf("\nEnter the duration: ");
                        scanf("%d",&duration);
                        duration_minutes=duration%100;/*calculate duration hours and minutes*/
                        duration_hours=(duration-duration_minutes)/100;                       
                }
        end_minutes=time_minutes+duration_minutes;/*calculate result*/
        end_hours=time_hours+duration_hours;
        if(end_minutes >=60)/*check if time minutes + duration minutes exceed the 60 minute limit*/
        {                        /*if so, then add 1 hour for 60 minutes*/
                end_minutes-=60;
                end_hours++;
        }
        if(end_hours>=24)/*check if time hours + duration hours exceed the 24 hours, if so*/
        {                /*then start counting from 0 again*/
                end_hours-=24;
        }
        if(end_hours<10)/*print exta 0 if hours is lesser then 10*/
        {       
                if(end_minutes<10)/*print extra 0 if minutes are lesser then 10 and hours also*/
                        printf("\nStarttime is %d. Duration is %d. Endtime is 0%d0%d.\n",time,duration,end_hours,end_minutes);
                else        /*print extra 0 for the hours, but not for the minutes*/
                        printf("\nStarttime is %d. Duration is %d. Endtime is 0%d%d.\n",time,duration,end_hours,end_minutes);
        char x;/*just to keep the result visible when this program is running in windows*/
        x=getch();
        return 0;
        }
        if(end_minutes<10)/*print extra 0 for the minutes, but not for the hours*/
                        printf("\nStarttime is %d. Duration is %d. Endtime is %d0%d.\n",time,duration,end_hours,end_minutes);
        char x;/*just to keep the result visible when the program is running in windows*/
        x=getch();
        return 0;
}

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i've attached the source and executables (both for linux and windows) so you can take a look yourself :)


thanks in advance

Yeah there is a lot easier way to code it. It's called perl. hehehe

Nice little proggy, when I get to a faster connection, I will check it out.