
January 23rd, 2003, 07:04 PM
#1
.:Hexadecimal Question:.
.:Hexadecimal Question:.
I’m really sorry to have to ask this question…
I know I should have learned the base16 numbering system a lil’ earlier..
I thought that Hex used 09, AF. But I’ve seen hex values like 9h?
Again I feel really stupid for having to ask ;)
yeah, I\'m gonna need that by friday...

January 23rd, 2003, 07:13 PM
#2
9h probably means 09 in hex (h denotes hex) so
09 hex 09h and 0x09 are all references to hex...
/nebulus
EDIT: Note this is necessary because 09 could be 09 in decimal (or a bunch of other bases). Wouldn't really matter 09 hex = 09 dec, but if the first digit wasn't a 0...then we would have some differences...
There is only one constant, one universal, it is the only real truth: causality. Action. Reaction. Cause and effect...There is no escape from it, we are forever slaves to it. Our only hope, our only peace is to understand it, to understand the 'why'. 'Why' is what separates us from them, you from me. 'Why' is the only real social power, without it you are powerless.
(Merovingian  Matrix Reloaded)

January 23rd, 2003, 07:14 PM
#3
ok, here this should put your mind at ease. from a RAMA walkthrough, a game that is hard to beat
A Primer on Arithmetic in Bases Other Than 10
The ordinary arithmetic problems we're used to seeing are all based on decimal (or base10) numbers, but systems using a base other than 10 are possible. In all systems, the position of a digit in a number determines the value it contributes; for example, the base10 number 2347 represents an implied addition problem:
2347 (10) = 2 x 1000
+ 3 x 100
+ 4 x 10
+ 7 x 1
Here we've included "(10)" after the number to emphasize that base 10 is being used. Note that the value multiplied by each digit increases by a factor of 10 as you move each position to the left, with the rightmost digit always representing ones. This use of the base to distinguish the role of each digit in a number is the key to understanding arithmetic in all bases. For example, the same sequence of digits in base 8 (octal) would translate to
2347 (8) = 2 x 512
+ 3 x 64
+ 4 x 8
+ 7 x 1
= 1255 (10)
Again, note that the value multiplied by each digit increases by a factor of 8 (the base) as you move each position to the left. These multipliers are referred to as powers of the base; for example,
Base 10Base 8
10 = 10 8 = 8
100 = 10 x 10 64 = 8 x 8
1000 = 10 x 10 x 10512 = 8 x 8 x 8
etc.
As seen in the conversion above, it's fairly easy to translate a nondecimal number into base 10, but the opposite conversion is a bit trickier. The procedure can best be illustrated by means of a specific problem, for example converting the decimal number 1255 (10) into base 8.
First, we begin by finding the largest power of the base present in the starting number. Since 8 x 8 x 8 x 8 = 4096 (10) is larger than 1255 (10), we next try 8 x 8 x 8 = 512 (10), which does factor at least once into 1255 (10):
1255 = 2 x 512 + remainder
In fact, 2 multiples of 512 (10) can be found in 1255 (10)  this 2 then becomes the first digit in our base8 equivalent.
To find the next base8 digit, start by removing the effect of the first digit, which changes the starting number from 1255 (10) to 231 (10):
1255  2 x 512 = 231
The procedure is repeated with the new starting number and the next smaller power of 8 to come up with the second base8 digit:
231 = 3 x 64 + remainder
Continuing the process eventually results in the definition of all base8 digits:
1255 (10) = 2 x 512
+ 3 x 64
+ 4 x 8
+ 7 x 1
= 2347 (8)
Any single digit in a number can never be as large as the base  the maximum digit in a decimal number is 9, and the maximum in a base8 number is 7. For bases larger than 10, we must introduce other symbols for values above 9  letters are usually the convention. In base 16 (hexadecimal), we have the possible digits
0 1 2 3 4 5 6 7 8 9 A B C D E F
For example, C (16) is equivalent to 12 (10).
Unless you have a translating calculator or other aid, it's usually easiest to solve complex arithmetic problems in nondecimal bases by first converting all numbers to base 10, performing the arithmetic, then converting the answer back to the desired base. For simple addition problems, an analog of the decimal columnar method may be used; for example in base 8,
1 < carry digit 5 3 + 2 7 1 0 2
Here are some examples of arithmetic problems in various bases:
Base 3Decimal Equivalent
1 + 2 = 101 + 2 = 3
10  1 = 23  1 = 2
21 + 12 = 1107 + 5 = 12
21  12 = 27  5 = 2
1201  111 = 12046  13 = 33
Base 8Decimal Equivalent
2 + 4 = 62 + 4 = 6
7  2 = 57  2 = 5
53 + 27 = 10243 + 23 = 66
52  41 = 1142  33 = 9
13053 + 17345 = 324205675 + 7909 = 13584
Base 16Decimal Equivalent
A + 4 = E10 + 4 = 14
D  B = 213  11 = 2
24 + 12 = 3636 + 18 = 54
FF  AA = 55255  170 = 85
1F40 + 5A8F = 79CF8000 + 23183 = 31183
 Trying is the first step towards failure. the moral is never try.
 It\'s like something out of that twilighty show about that zone.
Homer J Simpson

January 23rd, 2003, 07:25 PM
#4
yes, nebulus200  that clears things up.
thank you very much...
::embarrassed::
:)
yeah, I\'m gonna need that by friday...

January 23rd, 2003, 10:01 PM
#5
yes, nebulus2000 is correct its only impling hex
ex: 0x09h(were h stands for hex)
ex: 09b(were b stands for binary)
ex: 09o(were o stands for octal)
Tampa, don't fill embarrased we all can't know everything.
oops! your're right hex only goes thru 09, AF.
just thought I'll add that

January 24th, 2003, 03:28 AM
#6
ex: 09b(were b stands for binary)
LOL, phaza7, when did you last see a binary number with 9 in it?? Sorry, I just had to point this one out.
Cheers,
cgkanchi

January 24th, 2003, 01:32 PM
#7
Neat Lil' Chart for BIN <> HEX  I got it from "Art of Assembly" online tutorial btw mathgirl32 sent me the link (Cool...)
 http://www.it.uom.gr/project/assembly/contents.htm
 http://cs.smith.edu/~thiebaut/ArtOfA.../artofasm.html
_Binary__Hexadecimal
_0000___ 0
_0001___ 1
_0010___ 2
_0011___ 3
_0100___ 4
_0101___ 5
_0110___ 6
_0111___ 7
_1000___ 8
_1001___ 9
_1010___ A
_1011___ B
_1100___ C
_1101___ D
_1110___ E
_1111___ F
To convert a hexadecimal number into a binary number, simply substitute the corresponding four bits for each hexadecimal digit in the number. For example, to convert 0ABCDh into a binary value, simply convert each hexadecimal digit according to the table above:
0 A B C D Hexadecimal
0000 1010 1011 1100 1101 Binary
yeah, I\'m gonna need that by friday...
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