July 5th, 2003, 09:01 PM
There are some thing's in life that are quite diffiult to truly understand, and when you finally get it , it's like a revelation, and usually never forgotton. For me my present nightmare is subnetting. Yes I've had the lecture's, read the book's, tried all the method's, and before you ask "yes--of course I've searched Google. But what I was looking for was a very, very, very simple method of calculation "No--not with an IP calculator"I have come across a site Http://www.cscug.org/Presentations/S..._Your_Head.pdf which claims to enable you to "Subnet in you head in 90 Minutes" Ha Ha. I don't think so, but who knows.I would be interested to hear of any simple method used with success by AO member's
Computer says no
July 5th, 2003, 09:18 PM
Well with subnetting, the key (as far as I found) is to get a class C address down pat before you even attempt A & B (which use the same method).
How your only SM (subnet mask) possibilities for a Class C are 252 (6 bits), 248 (5 Bits), 240 (4 bits), 224 (3 bits), 192 (2 Bits) because you can only borrow 2 - 6 bits. It's useful to have those numbers memorized, or at least I think so.
2^number of bits borrowed will give you your subnets
2^bits left will give you your hosts / subnet
If i borrow 4 bits.
I'll have 2^4 = 16 subnets and I'll have 2^(8-4) = 2^4 = 16 hosts/subnet.
Well I have my Class C possibilities memorized (or look above), so if I borrow 4 bits my SM is 255.255.255.240. Say my network address was 18.104.22.168.
My first subnet would start @ 22.214.171.124 and go to 126.96.36.199, since it contains my original network address it is an unusable subnet.
The Next subnet would contain 16 hosts (determined above) and start with 188.8.131.52.... to get 16 hosts it would have to end at 184.108.40.206. This subnet is useable. 220.127.116.11 would be the Subnet Network Address and 18.104.22.168 would be the Subnet Broadcast address. We'd then keep counting up by 16s until we go to the last grouping which would be
22.214.171.124 - 126.96.36.199 which would be unusable because it contains the original broadcast address....
After you get class C subnetting down pat.. you can start working with the others (A&B)... I'll give ya a hand with them if you require it.. and if this was at all useful too ya.. throw me a PM if you need any help
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