A simple program with a tough logic!!!

[sec_ware]

Ok.

First: Create these string-arrays, for example with

	char one[3][5]={"zero","one","two"};   // HORRIBLE! :D
	//test:
            printf("%s",one[1]);

Second: get the digits, as suggested, of your number, for example

...
thousands=int(your_number)/1000;
your_number-=1000*thousands;
...
hundreds=int(your_number)/100 ;
your_number-=100*hundreds;
...

Be careful if the number after the "hundreds"-step is smaller than 20 -> additional cases.

Third: Print out according to the way you want to present the number
for example with

...
if (thousands!=0)
   printf("... %s thousand\t",ones[thousands]);
if (hundredss!=0)
   printf("... %s hundred\t",ones[hundreds]);
...

Remark: this is all c.


/edit:about your problem: 99000
you can solve it writing a recursive function print_the_number:

...
if (thousands!=0)
   printf("... %s thousand\t",print_the_number(thousands));
...

where print_the_number is again the same function with which
you initially wanted to print your starting number (recursive approach).

[akshayakrsh]

hey sec_ware
now i got the point what u wanted to say(i suppose)
will hav a work on that thing
n tell u what figures out
but still check out the link given SirDice, which is:
http://search.cpan.org/~rvasicek/Li....07/Num2Word.pm

thank u

[skiddieleet]

I hope you're not in my class cause you're a couple of weeks late on this assignment.

[akshayakrsh]

hey h3r3tic
yes i m late for the class u say
but plz tell me what's that class and what it is about
i'll be glad to know that
thnx

[Guus]

Oh, come on, do at least -something- yourself.

AO members have been more than helpful. If you want them to write the damn thing completely, ask that instead, but stop giving 'subtle' hints for more information.

With all the information you've been given, you should be able to do it yourself by now.

[skiddieleet]

Here is the logic we used. We would have functions for each category such as single digits, teens, tens (twenty, thirty...), hundreds, thousands... then it sort of repeats from there. So we had a function to convert each case to a string down the line. Here is a little of the code.

static char * digitToString(int number)
/* precondition: number < 10  */	
{
   char * word = (char *)malloc(8);
   if(word == NULL)
   {
      fprintf(stderr, "out of memory in digitToString\n");
      exit(1);
   }	
   if(number == 0)	return strcpy(word,"zero");
.
.
.
static char * teensToString(int number)
/* precondition: 10 < number < 20 */
{
   char * word = (char *)malloc(12);	
   if(word == NULL)
   {
      fprintf(stderr, "out of memory in teensToString\n");
      exit(1);
   }	
   if(number == 11) return strcpy(word,"eleven");
.
.
.
static char * tensPrefix(int number)
/* precondition: number is a multiple of 10 less than 100 */
{
   char * word = (char *)malloc(8);	
   if(word == NULL)
   {
      fprintf(stderr, "out of memory in tensPrefix\n");
      exit(1);
   }	
   if(number == 10) return strcpy(word,"ten");
.
.
.
static char * under100 (int number)
/* precondition: number < 100 */
{
   if(number < 10)
      return digitToString(number);
   else if(number % 10 == 0)
      return tensPrefix(number);
   else if(10 < number && number < 20)
      return teensToString(number);
   else
   {
      char * temp = tensPrefix(number/10*10);
      char * word = (char *)malloc(24);
      if(word == NULL)
      {
         fprintf(stderr, "out of memeory in digitToString\n");
         exit(1);
      }
.
.
.
static char * under1000(int number)
/* precondition: number < 1000 */
{
   if(number < 100)
      return (char*)under100(number);
   else
   {
      if(number % 100 == 0)
      {
         char * temp = digitToString(number/100);
         char * word = (char *)malloc(20);
         if(word == NULL)
         {
            fprintf(stderr, "out of memory in under1000\n");
            exit(1);
         }	
         strcpy(word, temp);
         free(temp);
         strcat(word, "-hundred");
         return word;
      }
      else
      {	
         char * temp = digitToString(number/100);
         char * word = (char *)malloc(32);
         if(word == NULL)
         {
            fprintf(stderr, "out of memory in digitToString\n");
            exit(1);
         }
.
.
.
char * numToString(int number)
/* calls the previous functions accordingly */

I know there are many ways to do it, but that's how we did it for our assignment, in a nutshell. Hopefully you can piece it together from there. Our program just went from 0 - 1000000. Remember to free the memory you allocate once you're through with what is using it. Peace.

[sec_ware]

"And you shall not" misuse faithful AO members!

Puzzles, questions out of curiosity are a nice thing -
it keeps the brain "to be on the ball".
Some AO members like challenges like this, even if
they are simple from time to time.

Don't misuse the knowledge/skills/whatever of others
in order to get done what you (sic) are supposed to do.
Letting "us" solve your assignments without telling
us in advance so is not good behaviour.