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  1. #1
    Member Kamikaze Badger can only hope to improve
    Join Date
    Jul 2004
    Posts
    46

    General math functions header

    Sorry if this is the wrong place to post this, but since it said it was a place to share code...


    I got bored after chores .


    Code:
    /* General math functions header file, (c) Sam Tootell. This piece of code 
    ** was madeto be used openly and freely, as if under the GNU GPL.
    */
    
    double pi = 3.1428571428571428571428571428571; /*For use with geometric functions, which is currently just a circle area*/
    
    /*Addition*/
    
    float add(float value1=0.0, float value2=0.0, float value3=0.0, float value4=0.0, float value5=0.0)
     {
         float endValue = value1 + value2 + value3 + value4 + value5;
         
         /*cout << "\nThe sum is " << endValue << ".\n";*/
         /*printf("\nThe sum is %f.\n" endValue);*/
         
         return endValue;
         
     }
     
    
    /*Subtraction*/
    
    float subtract(float sub-value1 =0.0, float sub-value2=0.0, float sub-value3=0.0, float sub-value4=0.0, float sub-value5=0.0)
    
     {
         float sub-endValue = sub-value1 - subvalue2 - subvalue3 - subvalue4 - subvalue5;
         
         /*cout << "\nThe difference is " << sub-endValue; << ".\n";*/
         /*printf("\nThe difference is %f.\n" sub-endValue);*/
         
         return sub-endValue;
         
     }
     
         
    /*Multiplication*/
    
    float multiply(float mult-value1=0.0, float mult-value2=0.0, float mult-value3=0.0, float mult-value4=0.0, float mult-value5=0.0)
    
     {
         float mult-endValue = mult-value1 * mult-value2 * mult-value3 * mult-value4 * mult-value5;
         
         /*cout << "\nThe product is " << mult-endValue << ".\n";*/
         /*printf("\nThe product is %f.\n" mult-endValue);*/
         
         return mult-endValue;
         
     }
     
         
    /*Division*/
    
    float divide(float divi-value1=0.0, divi-value2=0.0, divi-value3=0.0, divi-value4=0.0, divi-value5=0.0)
    
     {
         float divi-endValue = divi-value1 / divi-value2 / divi-value3 / divi-value4 / divi-value5;
         
         /*cout << "\nThe difference is " << divi-endValue << ".\n";*/
         /*printf("\nThe difference is %f.\n" divi-endValue);*/
         
         return divi-endValue;
         
     }
     
    /*Division, but gives remainders*/
     
     float remainder(float remain-value1, float remain-value2)
     
     {
         float remaniderOfValues1 = remain-value1 % remain-value2;
         float remainderOfValues2 = remain-value2 % remain-value1;
         
         /*cout << "\nThe remainder of << remain-value1 divided by remain-value2 is:" \
          " " << remainderOfValues1 << ". The remainder of " << remain-value2 << " divided" \
          " by " << remain-value1 << " is: " << remainderOfValues2 << "./n"; */
         
        /*printf("\nThe remainder of %f divided by %f is: %f.\n"remain-value1,remain-value2,remainderOfValues1);
          printf("\nThe remainder of %f divided by %f is: %f.\n"remain-value2,remain-value1,remainderOfValues2); */
         
         return remainderOfValues1; /*Not sure if I can return two at a time... I won't risk it*/
         
     }
     
     
    /*Pythagoream Theorem*/
    
    float pythTheorem(float a, float b)
    
     {
         
         float c = a^2 + b^2;
         
         /*cout << "\nFor << a << "^2 and << b << "^2, the result is << c << "^2.\n;*/
         /*printf("\nFor %f^2 and %f^2, the result is %f^2.\n" a,b,c);*/
         
         return c;
         
     }
     
     /*Exponentation*/
     
     float exponent(float exp-value1, float exp-value2)
     
      {
          float exp-endValue = exp-value1 ^ exp-value2;
          
          /*cout << "\nThe exponentation of " << exp-value1 << " and " << exp-value2 << " is " << \
           exp-EndValue << ".\n*/
          
          /*printf("\nThe exponentation of %f and %f is %f\n" exp-value1, exp-value2, exp-endValue);*/
          
          return exp-endValue;
          
      }
    
    /*================Geometry================*/
    
    /*Circle area*/
    
    float circleArea(float radius)
    
     {
         double area = pi * (radius ^ 2);
         
         /*cout << "\nFor radius = " << radius << ", the result is: \n " << area << "\n"*/
         /*printf("\nFor radius %f, the result is:\n%f\n" radius, area);*/
         
         return area;
         
     }
     
     
    /*Circle circumference*/
    
    float circleCircum(float radius-circ)
    
     {
          double circumference = 2*pi*radius-circ;
         
         /*cout << "\nFor radius = " << radius-circ << ", the circle circumference is: " << circumference << ".\n";
         /*printf("\nFor radius = %f, the circle circumference is: %f.\n" radius-circ, circumference);*/
         
          return circumference;
          
     }     
          
     
    
    /*Cube Volume*/
    
    float cubeVolume(float side)
    
     {
         float volume = side^3;
         
         /*cout << "\nFor any side of the cube being " << side << " units, the volume is " << volume << " units^3.\n";
         /*printf("\nFor any side of the cube being %f units, the volume is %f units^3.\n" side, volume*/
         
         return volume;
         
     }
     
    /* I'll work on more geometry later, and maybe even put in prompting functions... no guarantee*/
    Hope you can get some use out of it .

    EDIT: Added some more on.
    Tell me if you think I\'m spamming or doing something stupid, please.

  2. #2
    Elite Hacker skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute skiddieleet has a reputation beyond repute
    Join Date
    Mar 2003
    Posts
    1,407
    lol, you must be really bored. All I have to say is why not use
    #define PI 3.14159...
    instead of what you had? Peace.

  3. #3
    Member Kamikaze Badger can only hope to improve
    Join Date
    Jul 2004
    Posts
    46
    Good question...


    So, updated now, with your advice, and some other thinkanating:


    Code:
    /* General math functions header file, (c) Sam Tootell. This piece of code 
    ** was madeto be used openly and freely, as if under the GNU GPL.
    */
    
    /*double pi = 3.1428571428571428571428571428571; /*For use with geometric functions, which is currently just a circle area*/ */
    
    #define PI = 3.142857;
    
    /*Addition*/
    
    float add(float value1=0, float value2=0, float value3=0, float value4=0, float value5=0)
     {
         float endValue = value1 + value2 + value3 + value4 + value5;
         
         /*cout &lt;&lt; "\nThe sum is " &lt;&lt; endValue &lt;&lt; ".\n";*/
         /*printf("\nThe sum is %f.\n" endValue);*/
         
         return endValue;
         
     }
     
    
    /*Subtraction*/
    
    float subtract(float sub-value1=0, float sub-value2=0, float sub-value3=0, float sub-value4=0, float sub-value5=0)
    
     {
         float sub-endValue = sub-value1 - subvalue2 - subvalue3 - subvalue4 - subvalue5;
         
         /*cout &lt;&lt; "\nThe difference is " &lt;&lt; sub-endValue; &lt;&lt; ".\n";*/
         /*printf("\nThe difference is %f.\n" sub-endValue);*/
         
         return sub-endValue;
         
     }
     
         
    /*Multiplication*/
    
    float multiply(float mult-value1=0, float mult-value2=0, float mult-value3=0, float mult-value4=0, float mult-value5=0)
    
     {
         float mult-endValue = mult-value1 * mult-value2 * mult-value3 * mult-value4 * mult-value5;
         
         /*cout &lt;&lt; "\nThe product is " &lt;&lt; mult-endValue &lt;&lt; ".\n";*/
         /*printf("\nThe product is %f.\n" mult-endValue);*/
         
         return mult-endValue;
         
     }
     
         
    /*Division*/
    
    float divide(float divi-value1=0, divi-value2=0, divi-value3=0, divi-value4=0, divi-value5=0)
    
     {
         float divi-endValue = divi-value1 / divi-value2 / divi-value3 / divi-value4 / divi-value5;
         
         /*cout &lt;&lt; "\nThe difference is " &lt;&lt; divi-endValue &lt;&lt; ".\n";*/
         /*printf("\nThe difference is %f.\n" divi-endValue);*/
         
         return divi-endValue;
         
     }
     
    /*Division, but gives remainders*/
     
     float remainder(float remain-value1, float remain-value2)
     
     {
         float remaniderOfValues1 = remain-value1 % remain-value2;
         float remainderOfValues2 = remain-value2 % remain-value1;
         
         /*cout &lt;&lt; "\nThe remainder of &lt;&lt; remain-value1 divided by remain-value2 is:" \
          " " &lt;&lt; remainderOfValues1 &lt;&lt; ". The remainder of " &lt;&lt; remain-value2 &lt;&lt; " divided" \
          " by " &lt;&lt; remain-value1 &lt;&lt; " is: " &lt;&lt; remainderOfValues2 &lt;&lt; "./n"; */
         
        /*printf("\nThe remainder of %f divided by %f is: %f.\n"remain-value1,remain-value2,remainderOfValues1);
          printf("\nThe remainder of %f divided by %f is: %f.\n"remain-value2,remain-value1,remainderOfValues2); */
         
         return remainderOfValues1; /*Not sure if I can return two at a time... I won't risk it*/
         
     }
     
     
    /*Pythagoream Theorem*/
    
    float pythTheorem(float a, float b)
    
     {
         
         float c = a^2 + b^2;
         
         /*cout &lt;&lt; "\nFor &lt;&lt; a &lt;&lt; "^2 and &lt;&lt; b &lt;&lt; "^2, the result is &lt;&lt; c &lt;&lt; "^2.\n;*/
         /*printf("\nFor %f^2 and %f^2, the result is %f^2.\n" a,b,c);*/
         
         return c;
         
     }
     
     /*Exponentation*/
     
     float exponent(float exp-value1, float exp-value2)
     
      {
          float exp-endValue = exp-value1 ^ exp-value2;
          
          /*cout &lt;&lt; "\nThe exponentation of " &lt;&lt; exp-value1 &lt;&lt; " and " &lt;&lt; exp-value2 &lt;&lt; " is " &lt;&lt; \
           exp-EndValue &lt;&lt; ".\n*/
          
          /*printf("\nThe exponentation of %f and %f is %f\n" exp-value1, exp-value2, exp-endValue);*/
          
          return exp-endValue;
          
      }
    
    /*================Geometry================*/
    
    /*Circle area*/
    
    float circleArea(float radius)
    
     {
         double area = PI * (radius ^ 2);
         
         /*cout &lt;&lt; "\nFor radius = " &lt;&lt; radius &lt;&lt; ", the result is: \n " &lt;&lt; area &lt;&lt; "\n"*/
         /*printf("\nFor radius %f, the result is:\n%f\n" radius, area);*/
         
         return area;
         
     }
     
     
    /*Circle circumference*/
    
    float circleCircum(float radius-circ)
    
     {
          double circumference = 2*PI*radius-circ;
         
         /*cout &lt;&lt; "\nFor radius = " &lt;&lt; radius-circ &lt;&lt; ", the circle circumference is: " &lt;&lt; circumference &lt;&lt; ".\n";
         /*printf("\nFor radius = %f, the circle circumference is: %f.\n" radius-circ, circumference);*/
         
          return circumference;
          
     }     
          
     
    
    /*Cube Volume*/
    
    float cubeVolume(float side)
    
     {
         float volume = side^3;
         
         /*cout &lt;&lt; "\nFor any side of the cube being " &lt;&lt; side &lt;&lt; " units, the volume is " &lt;&lt; volume &lt;&lt; " units^3.\n";
         /*printf("\nFor any side of the cube being %f units, the volume is %f units^3.\n" side, volume*/
         
         return volume;
         
     }
     
    /* I'll work on more geometry later, and maybe even put in prompting functions... no guarantee*/

    Yea, I was REALLY bored that night .
    Tell me if you think I\'m spamming or doing something stupid, please.

  4. #4
    Senior Member jdenny jdenny jdenny jdenny jdenny jdenny jdenny jdenny jdenny jdenny jdenny
    Join Date
    Jul 2002
    Posts
    339
    Sorry to bring back "old" thread, but I just came across this one...

    1. I know in school they told us PI ~ 22/7, but PI is NOT 22/7. PI is 3.141592653589793238...
    Just google for 3.1415926535 and you'll find the higher precision values (I've seen up to 50 digits).

    2. Have you tried to make use of the header file (#include and anything)?
    The use of dash in variable names caught my eyes right away, also the first line of subtrack().
    But then I let my compiler to decide anyway, and yes, it complains...

    Now that's what I call bored.

    Peace always,
    &lt;jdenny&gt;
    Always listen to experts. They\'ll tell you what can\'t be done and why. Then go and do it. -- Robert Heinlein
    I\'m basically a very lazy person who likes to get credit for things other people actually do. -- Linus Torvalds


  5. #5
    Senior Member sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute sec_ware has a reputation beyond repute
    Join Date
    Mar 2004
    Posts
    557
    Hi

    ...which brings me to the most useless url I have ever seen:

    http://3.141592653589793238462643383...974944592.com/

    edit: the url in two pieces
    3.141592653589793238462643383279502
    884197169399375105820974944592.com





    Cheers.
    If the only tool you have is a hammer, you tend to see every problem as a nail.
    (Abraham Maslow, Psychologist, 1908-70)

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