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Thread: SQL Injection Wargame

  1. #1
    Junior Member
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    Thumbs up SQL Injection Wargame

    Exploiting an SQL Inject attack involves solving a puzzle that is a cross between Hangman and 20 Questions. It needs a little understanding of SQL and a great deal of cunning.

    Try your Hacking skills against this test system. It takes you through the exploit step-by-step.

    The SQL Injection attack allows external users to read details from the database. In a well designed system this will only include data that is available to the public anyway. In a poorly designed system this may allow external users to discover other users' passwords.

    Want to know what the hacker do?
    See this video http://w13.easy-share.com/1699826799.html

  2. #2
    Senior Member nihil's Avatar
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    Hello ekosch,

    Welcome to AO

    I have amended the title of your post so that it will get a better audience

  3. #3
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    Lightbulb Hacking Website

    Exploiting an SQL Inject attack involves solving a puzzle that is a cross between Hangman and 20 Questions. It needs a little understanding of SQL and a great deal of cunning.

    Try your Hacking skills against this test system. It takes you through the exploit step-by-step.

    The SQL Injection attack allows external users to read details from the database. In a well designed system this will only include data that is available to the public anyway. In a poorly designed system this may allow external users to discover other users' passwords.

    Try these steps:
    To gain access and find a user name. Enter the string 'OR''=' as both user name and password in the frame on the right. This should get you logged in as a user (jake happens to be the first user in the table). This tells you that Jake is a user and it allows you to access his account - but it does not tell you his password.

    Find out if Jake's password includes the letter "w". Enter xxx as user name and enter the following string as the password: ' OR EXISTS(SELECT * FROM users WHERE name='jake' AND password LIKE '%w%') AND ''='

    Find out if Jake's password has "w" as the third letter. Enter xxx as user name and enter the following string as the password: ' OR EXISTS(SELECT * FROM users WHERE name='jake' AND password LIKE '__w%') AND ''='

    See the video how is work http://w13.easy-share.com/1699826799.html

  4. #4
    Banned
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    I moved this last post here, too - it was in Tutorial Submissions, where it doesn't belong.

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