-
March 10th, 2011, 05:29 PM
#1
Member
John the ripper charset
Hey all, I have a question about John the Ripper.
I know that a password that is 7 characters long and used only 4 keys. I know what the three keys are, but I don't know how to make a custom charset. I have edited the john.conf file to have the following:
Code:
[Incremental:Custom]
File = custom.chr
MinLen = 7
MaxLen = 7
CharCount = 3
Now i just don't know how to make the custom.chr so that it only contains the 4 keys 'asdf'
Any ideas?
Thanks
Last edited by Phalse; March 10th, 2011 at 05:37 PM.
Similar Threads
-
By sploiterwannabe in forum Newbie Security Questions
Replies: 6
Last Post: May 23rd, 2005, 05:34 PM
-
By !mitationRust in forum Cosmos
Replies: 13
Last Post: August 2nd, 2004, 04:42 PM
-
By lpaulgib in forum Cryptography, Steganography, etc.
Replies: 4
Last Post: April 15th, 2004, 01:42 AM
-
By steve.milner in forum Tech Humor
Replies: 0
Last Post: July 26th, 2003, 09:09 PM
-
By I am a cracker in forum The Security Tutorials Forum
Replies: 2
Last Post: February 24th, 2002, 11:01 PM
Posting Permissions
- You may not post new threads
- You may not post replies
- You may not post attachments
- You may not edit your posts
-
Forum Rules
|
|