Stuck on C++ Problem

Let me give you some of the details of what i am tring to do here.
I'm creating a mult. table. the program will prompt users to enter a table from 2 to 12, it will also ask if you want to run the program again. this is where I get lost. This is what I have so far.

# include <iostream>
# include <iomanip>
using namespace std;
int main ()
{
int table;
cout << "What size table would you like (2 to 12)? ";
cin >> table;
cout << " | ";
for (int a=0; a <=table; a++)
cout << setw (5) << a;
cout << endl;
cout << "------------------------------------------------------------------------------------------" << endl;
for (int across=0; across <=table; across++)
{
cout << setw (3) << across << setw (3) << " | " << ' ';
for (int down=0; down <=table; down++)
cout << setw (5) << down * across;
cout << endl;
}
return 0;
}

See where would I put the loop statement in and which one should I use?
I ran is so I know this part works.

Thank you all.

It's been a while since I did C++, but if you're trying to loop it until the user wants to exit, just do-while loop it, ********** denotes added code

# include <iostream>
# include <iomanip>
using namespace std;
int main ()
{
int table;
int number; **********
Do **********
{
cout << "What size table would you like (2 to 12)? ";
cin >> table;
cout << " | ";
for (int a=0; a <=table; a++)
cout << setw (5) << a;
cout << endl;
cout << "------------------------------------------------------------------------------------------" << endl;
for (int across=0; across <=table; across++)
{
cout << setw (3) << across << setw (3) << " | " << ' ';
for (int down=0; down <=table; down++)
cout << setw (5) << down * across;
cout << endl;
cout << "do this again? (No = 1 Yes = 1)";*********
cin >> number;*********
} while (number = 0);********
}
return 0;

you can do this with words also ('y' || 'Y') but it depends on the person

coming up with errors, does
cout << "do this again? (no=1 yes=1)"; look right?
or should it be (no = 0 and yes = 1)

error given is syntax error return
and line 28 function should return a value void return type assumed

Code:

---


# include <iostream>
# include <iomanip>
using namespace std;
int main ()
{
        char cStop[1];
        int table;       
       
        do
        {
       
                cout << "What size table would you like (2 to 12)? ";
                cin >> table;
                cout << " | ";
       
                for (int a=0; a <=table; a++)
                        cout << setw (5) << a;

                cout << endl;
                cout <<"------------------------------------------------------------------------------------------" << endl;
       
                for (int across=0; across <=table; across++)
                {
                        cout << setw (3) << across << setw (3) << " | " << ' ';
                        for (int down=0; down <=table; down++)
                        cout << setw (5) << down * across;
                        cout << endl;
                }
       
                cout << "Do you want to continue? (y/n): ";
                cin >> cStop;
        }
        while( strcmp( cStop, "n" ) );
        return 0;
}

---

bombbomb's code has 2 little errors:
"Do" should be "do" : (C/C++ is case sensitive)
"while( number = 0)" should be "while( number == 0)"


Ammo

strcmp what does this mean?

and what does [1] the brackets mean? I'm just tring to understand, I need to know why it works this way. otherwise I ll never learn. LOL it

ok,

the [1] means you are declaring a array of characters of size 1,
the strcmp is a function that compares a string (ie: an array of char) to another.

I could also have used

#include <string>

String sStop;

while( sStop != "n" )

string is a class that does strings in a "beautifuler" way...

Ammo

heh, well, actually, I was dumb:
I didn't need the [1] and the strcmp.. (duh),
a simple char cStop and while( cStope != 'n' ) would have done..

Here is a different way to do the same thing. The only thing I added that you did not have was a 'clear screen' command. When running a program over and over it can get a little messy having everything on one screen.

Code:

---

# include <iostream>
# include <iomanip>
using namespace std;
int main ()
{
        int table;
        char runAgain = 'y';
 
        do
        {
                cout << "What size table would you like (2 to 12)? ";
                cin >> table;
                cout << " | ";
               
                for (int a=0; a <=table; a++)
                cout << setw (5) << a;
                cout << endl;
                cout << "----------------------------------------------------" << endl;
       
                for (int across=0; across <=table; across++)
                {
                        cout << setw (3) << across << setw (3) << " | " << ' ';
                        for (int down=0; down <=table; down++)
                        cout << setw (5) << down * across;
                        cout << endl;
                }

        cout << "Run again?: ";
        cin >> runAgain;
        system("cls");
        }

        while (runAgain == 'y' || runAgain == 'Y');
        return 0;
}

---

Ok heres another question I have?
I need to produce something like this:

integer sum factorial
1 1 1
2 3 2
3 6 6
4 10 24
5 15 120
6 21 720
and so on untill it hits the count: count meaning value that was entered by user.
I can see sum is added by the next integer to get next sum and the same goes for factorial. just wondering how I sould go about starting this one?

I know I should

# include <iostream>
usning namespace std;
int main ()
{
int sum, fact, value;
cout << "What upper limit would you like? ";
cin >> count;

Sould I include math in this? and what sould I use an if statement or a for statement?

just for the sake of it, on the first one...

Code:

---

#includes...

void main() {
char repeat_program ;
for( ;; ) {          //forever

 .        .        .
do {
        cout << "Want to repeat this?\n" ;
        cin >> repeat_program ;
        repeat_program = toupper( repeat_program ) ;  //since we are including iomanip
        if( repeat_program == 'Y' ) break ;
} while( repeat_program != 'N' ) ;
// force selection of 'y' or 'n'
}

---

Thank you all for the help you have provided me with. I apperciate it alot. Still haveing problems with the last one if anyone wants to take a stabe at it or just drop me a hint as to how I should go abouts starting this one. but again my thanks to you all Greenies coming your way.

I joined collage to be in networking and here I am programming, go figure that one out.