The C challenge

Ok folks ..

I've come across a really neat C problem.Try coding this !



" A program in C to print whether a given number is even or odd without using any

conditional statements and loops ! "


I'm sure someone will do this ! ...

Code:

---


#include <stdio.h>

int main(void)
{
      int odd;
      int even;
      printf("enter an even number: ");
      scanf("%d",&even);
      printf("\n%d is an even number.",even);
     
      printf("\n\nEnter an odd number: ");
      scanf("%d",&odd);
      printf("\n%d is an odd number.",odd);
     
      return 0;
}

---

problem solved ;)

This is pretty easy once you know how to distinguish it and analyze the problem. I'll even have it show some text like "ODD" and "EVEN" for you... :D

Code:

---

#include <stdio.h>

int main(void)
{
    int input;
    char strings[1][5];
   
    strcpy(strings[0], "ODD\0");
    strcpy(strings[1], "EVEN\0");

    printf("Give me a number: ");
    scanf("%i", &input);

    printf("This is a(n) %s number!", &strings[(input+1)%2]);

    getch();
    return 0;
}

---

ok, an serious answer then:

i'm not sure if this is allowed, but i think it is:

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
     
      int number, temp;

      printf("Enter a number: ");
      scanf("%d",&number);

      temp=number%2;
      switch(temp)
      {
              case 0:
                      printf("\n%d is an even number",number);
                      break;
              default:
                      printf("\n%d is an odd number",number);
                      break;
      }
      return EXIT_SUCCESS;
}

---

You got it right folks !!!! ... This question was actually asked for a job interview here !. The logic is pretty simple and because of the fact that it is so simple, some people never solve it .

I don't think I would get that job :(. I'm guessing it was lepricaun's first and Tim_axe's programs that were right? lepricaun's second had a switch which is a conditional statement, so that's not correct is it? /me works on some code. Peace.

Quote:

---

lepricaun's second had a switch which is a conditional statement, so that's not correct is it?

---

i also don't
think my second is allowed, but the first was more of a joke, since some of these questions are so tricky, that you think it the hard way, while the solution is very simple....