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Re: Physics Problem
Quote:
Originally posted here by er0k
Yes this is my homework.
The summit of a mountain, 2085 m above base camp, is measured on a map to be 4580 m horizontally from the camp in a direction of 32.4 degrees west of north. What are the x, y, and z components of the dispacement vector from camp to summit? What is its length?
can anyone do that problem, i have completed it, and know how it works, but im getting really wacky answers when i try to test my answers. even though i know they are right.. someone who can just work it please..
edit: come on you engineers out there this problem is easy! :)
OK, there is two ways to get this, calculate (hyp)hypotenuse basic trig ratios, what was it.......oh yes Oscar/Had/a/Hunk/of/Apple ;) & use the pythagorean theorem.
2085sqr plus 4580sqr sum sqr 4586
sine cosine solve for H
H 2085 divide sin 32.4 X ....same exact value
I might be wrong here but I think it is
X 4580
Y 2085
Z 4586 double check.
Term spelling might be off.
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yeah thats the right way to do it, but its not the sin 32.4 its a bigger angle. i can't remember it, but this is old homework, to keep you all busy ill post a new one soon ;)
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Quote:
Originally posted here by er0k
yeah thats the right way to do it, but its not the sin 32.4 its a bigger angle. i can't remember it, but this is old homework, to keep you all busy ill post a new one soon
Make sure your calculator is in degrees and not radians. That should net you the same value I calculated with the Pythagorean theorem: z^2=x^2+y^2 where z is the hypotenuse of the right triangle. :D
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I just caught this thread, and I'll throw someting in:
Map Degree Measurement & Trig Degree Measurement are different. IE, North (0 degrees on a map) is 90 degrees on a trig circle. East is 90 degrees, while the trig equiv is 0 degrees. South is 180 degrees on a map, or 270 degrees in trig. West is 270 degrees on a map, while in trig that is 180 degrees. IIRC, to convert from map direction to trig direction, you subtract 270 degrees from the map direction.
That will probably clear up the problems with getting the correct coordinates/values.
Dang, now I'm starting to think about doing my Calculus homework. Derivitives and limits are so confusing when you want to find the general rule for something like a^x / (b-x^c)... :(
Did I mention the love/hate relationship with polynomials and above and finding their factors? ...
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Quote:
Originally posted here by !mitationRust
Make sure your calculator is in degrees and not radians. That should net you the same value I calculated with the Pythagorean theorem: z^2=x^2+y^2 where z is the hypotenuse of the right triangle. :D
if you take the 2085 /sin(32.4) you do not get the right answer. the angle is different. its larger. in fact 56.9 degrees west of north. in order to do the problem properly, you have something like this, which i will attach. Thank you all for your help, but ive long since had this problem figured out :)
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Quote:
Originally posted here by er0k
if you take the 2085 /sin(32.4) you do not get the right answer. the angle is different. its larger. in fact 56.9 degrees west of north. in order to do the problem properly, you have something like this, which i will attach. Thank you all for your help, but ive long since had this problem figured out :)
So that’s the final answer. I was thinking the angle inside the triangle was 32.4 not 56.9 but I may have misunderstood. It makes sense that you would have to calculate the new angle though; otherwise all you would be finding is the distance.