C++ Homework Help (while loop)?

#include <iostream.h>
#include <conio.h>

int number = 0;
int number2 = 0;
int response = 0;
while (response = 5)
{

void main ()

{
cout<<"Enter the first number: ";
cin>>number;
cout<<"Enter the second number: ";
cin>>number2;
cout<<"Menu Items\n 1)add\n 2)subutract\n 3)multiply\n 4)divide\n";
cin>>response;
if (response != 1-4)
{
cout<<"That is not a valid number"<<endl;
}

switch (response)
{
case 1:
cout<<number + number2<<endl;
break;
case 2:
cout<<number - number2<<endl;
break;
case 3:
cout<<number * number2<<endl;
break;
case 4:
cout<<number / number2<<endl;
break;
case 5:
cout<<response<<endl;
}

}


}

Basically I don't want the program to exit once I get an anser.
So I put in a while loop to equal 5 so every equation gets worked once, but I know it's not right and my reference book doesn't give much insight to what I'm supposed to do. Could someone help me by telling me where to put this while loop in?

It's C++ and I'm using the Micorosoft Visual, this is a ms-dos .exe so at the end of the program I get that "Press any key" thing.

Quote:

---

Originally posted by freeOn
cin>>response;
if (response != 1-4)
{
cout<<"That is not a valid number"<<endl;
}

---

Doesn't that equate to "If the response does not equal -3" ? I'll post something later once I test it out, I've been away from any C++ for a long time.

Your "while" is outside of main, by the way... I'm not even gonna guess if that works or not.

I'd take out the while (response == 5) and go with:

void main() {

while (response != "end") {

if (response < 1 && response > 4 && response != "end") {
cout << "1,2,3,4 or 'end'\n" << endl;
} // end response check

} // end while

} // end main

There are probably better ways to do this but it's quick-n-dirty and gets the job done, I think. This is without a compiler to check.

no that's all about saying that if a menu item doesn't equal 1,2,3,4. then print out "that is not a valid number".

I'm just looking for a while loop so the program repeats.

Hey vorlin It's a requirement to use the case/switch, or else I would do the same thing.

Here's something that I think would work.

Code:

---

#include <iostream.h>
#include <conio.h>

int number = 0;
int number2 = 0;
int response = 0;

void main()

{
        while(response != 5)
        {
                cout<<"Enter the first number: ";
                cin>>number;
                cout<<"Enter the second number: ";
                cin>>number2;
                cout<<"Menu Items\n 1)Add\n 2)Subutract\n 3)Multiply\n 4)Divide\n 5)Quit\n";
                cout<<"Command: ";
                cin>>response;
                cout<<endl;
                             
                               
                switch (response)
                {
                        case 1:
                        cout<<number<<" plus "<<number2<<" equals ";
                        cout<<number + number2<<endl;
                        break;
                        case 2:
                        cout<<number<<" minus "<<number2<<" equals ";
                        cout<<number - number2<<endl;
                        break;
                        case 3:
                        cout<<number<<" times "<<number2<<" equals ";
                        cout<<number * number2<<endl;
                        break;
                        case 4:
                        cout<<number<<" divided by "<<number2<<" equals ";
                        cout<<number / number2<<endl;
                        break;
                        default:
                        cout<<"Invalid Command."<<endl;
               
                }
                cout<<"-------"<<endl;
        }
}

---

EDIT: I know that there is no case for five, but the program will end itself before the user even sees the whole 'invalid command' bit. I still oughta have added an "any key to quit" part... Also, due to the data types (integers) this program will round the results... If you change the data types for Number and Number2 to "double" then you'll get much more accurate answers when decimals are involved in the input or if you are dividing.

oh cool, Terr you are the ****!. Thanks alot man it works and I also see what I was doing wrong. Thanks Alot!