I have nothing better to do with my time, so I make a simple Calculus math problem for you to figure out..... The first person to give me the right Solution will win a cookie.... Good luck....

System_0verload

A particle with a mass of 0.01 kg is moving along the x-axis. After t seconds the position of this particle is given (in meters) by the equation:

x(t)=1/48 t4 - 1/12 t3 - 15/8 t2+100

Using the time-interval [0,12] seconds:

1. At t = 0 the particle starts and moves backwards. What distance does it move backwards? (Answer rounded to two decimal places)

2. At what time will the velocity of the particle be identical to 5m/s? (Answer rounded to two decimal places)

3. What force is working on the particle when it is situated at x = 110 m? (Answer rounded to four decimal places)

4. What is the velocity of the particle at the moment that its acceleration is minimal? (Answer rounded to two decimal places)

NOTE: Use answers rounded to six decimal places in your calculations!!!