What 'C' output? And Why?

[Tedob1]

the question is what is the final value of x, not what is the last value printed out by the loop. if you print 'x' again after the loop ends, you'll see the final value of 'x' is 10

#include <iostream>
using namespace std;

void main()
{
for (int x=0; x<10;x++)
{
cout << x <<endl;
}
cout <<endl<<endl; //show it seperated from the loop output
cout <<"the final value of x is: "<< x <<endl;
return;

}

[Jabberwocky]

i believe that if the loop were written

for(int i =0; i<10; ++i)

it would be 10, because it would increment and then test.

but the way harbir has it written, it will fail once i hits 10.

[nebulus200]

Hey Tedob, I wanted to give you greenies, but the AP system thinks I have been a little to generous to you...you are absolutely correct, the final value of x would indeed be ten, I only considered inside the loop, but now maybe a question...you defined x in the loop...x outside the loop would be zero no? (damn I wish I was at work, would test that quick like...)

/neb

EDIT: undefined is what I meant, it should be undefined...sorry have always associated that with zero.

[Tedob1]

the loop made the value of x = 10, then failed. the value remains 10 unless you reset it. I ran the code before i posted it, and the value of x outside the loop is 10.

[harbir]

The thing here is that, we are not concerned about the number of times the loop will run, All we are concerned is the final value of X, I have tested it also, The final value of X is 10.
Explanation:
Simple, if the value of X is nine, then the loop will run, it is onlt when X turns to 10 the condition turns False and the control comes out of the loop. Therefore the final value of X is 10.

First even i got confused, But now i am sure, This answer is even right LOGICALLY.

[nebulus200]

Ok dang it, you made me vpn in and test it


int main(int argc,char * * argv)
{
// int ;
int i=0;
for(int x=0; x < 10; x++)
{
printf("Loop i: %i %i", i++, x);
}
printf("Loop i: %i %i", i, x);
}

Using g++
test.c: In function `int main(int, char**)':
test.c:13: name lookup of `x' changed for new ISO `for' scoping
test.c:9: using obsolete binding at `x'


I guess it depends on your compiler, but x should be outside the scope of the for loop; however, depending on how the compiler references/dereferences the variable, the value of 10 was probably still out in the same memory address and x wasn't dereferenced and disrupted but other things writing to the same memory, then you would still get x=10 depending on if your compiler lets you do that...

/neb

[coolnads]

Do this in C and ull get the value of x 10 ( after the lop is over ) like all the right ppl above said do this in Java and nebulus is right .....